#!/usr/bin/env python3
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
# MA 02110-1301, USA.

"""Continually runs a command and given arguemts

Helpful for running commands that only differ in the last arg
Use "exit", "quit", or "q" to exit program
"""

__all__ = ['main']
__author__ = "Cody A. Taylor ( codemister99@yahoo.com )"
__version__ = "0.3.2"

import sys
from os import system

def main():
    if len(sys.argv) == 1 or "--help" in sys.argv[1:]:
        print("Usage: {} command [repeated_args]".format(sys.argv[0].split("/")[-1]))
        sys.exit()

    print('Use "!exit", "!quit", or "!q" to exit program',
          'to add repeated arguments, start your args with @',
          'to remove arguments, use !!N with N being the number of characters to remove',
          sep="\n")

    cmd = " ".join(sys.argv[1:])

    while True:
        arg = input("{}: ".format(cmd))

        if arg.strip().lower() in {"!exit", "!quit", "!q"}:
            sys.exit()

        if arg.startswith("@"):
            cmd += arg[1:]
        elif arg.startswith("!!"):
            try:
                amount = int(arg.strip()[2:])
            except ValueError as err:
                print("Error:", err)
            else:
                cmd = cmd[:(len(cmd) - amount)]
        else:
            system("{} {}".format(cmd, arg))

if __name__ == "__main__":
    main()